ps | |
---|---|
링크 | acmicpc.net/… |
출처 | BOJ |
문제 번호 | 4792 |
문제명 | 레드 블루 스패닝 트리 |
레벨 | 플래티넘 3 |
분류 |
최소 신장 트리 |
시간복잡도 | O(V^2*α(V)) |
인풋사이즈 | V<=1000 |
사용한 언어 | Python |
제출기록 | 65932KB / 1060ms |
최고기록 | 1060ms |
해결날짜 | 2021/10/20 |
"""Solution code for "BOJ 4792. 레드 블루 스패닝 트리".
- Problem link: https://www.acmicpc.net/problem/4792
- Solution link: http://www.teferi.net/ps/problems/boj/4792
Tags: [MST]
"""
import sys
from teflib import disjointset
def minimum_spanning_tree(node_count, zero_edges, one_edges):
dsu = disjointset.DisjointSet(node_count)
component_count, total_cost = node_count, 0
total_cost = 0
for edges, cost in ((zero_edges, 0), (one_edges, 1)):
for u, v in edges:
try:
dsu.union(u, v, should_raise=True)
except ValueError:
continue
total_cost += cost
component_count -= 1
if component_count == 1:
return total_cost
def main():
while True:
n, m, k = [int(x) for x in sys.stdin.readline().split()]
if n == 0:
break
blue_edges, red_edges = [], []
for _ in range(m):
c, f, t = sys.stdin.readline().split()
if c == 'B':
blue_edges.append((int(f) - 1, int(t) - 1))
else:
red_edges.append((int(f) - 1, int(t) - 1))
min_blue_count = minimum_spanning_tree(n, red_edges, blue_edges)
min_red_count = minimum_spanning_tree(n, blue_edges, red_edges)
max_blue_count = n - 1 - min_red_count
is_possible = min_blue_count <= k <= max_blue_count
print('1' if is_possible else '0')
if __name__ == '__main__':
main()