• 퇴사에서 n의 범위를 늘린 버전. 풀이는 그쪽을 참고.

"""Solution code for "BOJ 15486. 퇴사 2".

- Problem link: https://www.acmicpc.net/problem/15486
- Solution link: http://www.teferi.net/ps/problems/boj/15486

Tags: [DP]
"""

import sys


def main():
    N = int(sys.stdin.readline())
    dp = [0] * (N + 1)
    for i in range(N):
        t_i, p_i = [int(x) for x in sys.stdin.readline().split()]
        if dp[i] > dp[i + 1]:
            dp[i + 1] = dp[i]
        if i + t_i <= N and dp[i] + p_i > dp[i + t_i]:
            dp[i + t_i] = dp[i] + p_i
    print(dp[N])


if __name__ == '__main__':
    main()